The additional pins of the lga socket
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The pins on the new Intel LGA-1151v2 socket have been shown to be completely unnecessary. According to an analysis carried out by Roman Hartung, also known as Der8auer on YouTube, it has been demonstrated through a series of tests that the existence of these pins are completely unnecessary for the normal use of a CPU.
Intel LGA-1151v2 socket is unnecessary
The new socket for Intel CPUs, the LGA-1151v2, implements a series of extra paints with the aim of providing a lower intensity load over those existing in the previous socket. This would provide us with greater stability and security when using the new brand CPUs and a greater power supply.
The in-depth analysis of this new socket together with the Z390 chipset left a very clear main ideal, and that is that the additional pins that this one implements are not necessary for the correct operation of the CPU and motherboard.
First, he physically removed the socket from a Z370 chipset board to test what current each pin could withstand, he subjected this to a current of up to 5A, which were supported if anything went wrong. After this, it simulated the operation of a Z270 Chipset with an Intel core i9-9900K, removing up to 18 pins in order to overload the rest, without errors or malfunctions.
Finally, he covered 69 pins of this same CPU and reinstalled it to see if it could withstand a higher intensity, for a continuous time, and indeed it was. This shows that the modifications implemented in this new socket are absolutely useless, since the CPU is perfectly functional without this series of pins.
Conclusion, the new LGA socket is quite unnecessary, at least for the normal use of a computer that assembles these new processors. Since the current pins perfectly supported the intensity that was supplied. It is possible that in unlocked CPUs and with powerful overclocks, these pins are more useful, otherwise, it is another marketing strategy to make us buy the product. What do you think about these seemingly unnecessary modifications?
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